a bag contains 4 green balls and 6 red balls another bag b contains 3 green and 4 red balls if one ball is drawn from each bag . Find the probability that both are green
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probability of green balls from 1st bag=4/10=0.4
". ". " ". ". 2nd bag=3/7=0.42
". ". " ". ". 2nd bag=3/7=0.42
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green balls 4
red balls 6
6+4=10
another bag
green 3
red 4
4+3=7
the probability that both are green is first is 4/10 2nd 3/7
red balls 6
6+4=10
another bag
green 3
red 4
4+3=7
the probability that both are green is first is 4/10 2nd 3/7
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