Question

A bag contains 4 mangoes and 5 oranges. In how many ways can i make a selection so as to take atleast one mango and one orange?

Answer 1

Step-by-step explanation:

Number of bananas in the bag = 5

\text{Number of ways such that there is at least one banana is selected = }2^5-2^0Number of ways such that there is at least one banana is selected = 2

5

−2

0

⇒ 32 - 1 = 31

Number of oranges in the bag = 4

\text{Number of ways such that there is at least one orange is selected = }2^4-2^0Number of ways such that there is at least one orange is selected = 2

4

−2

0

⇒ 16 - 1 = 15

Hence, Number of different ways which could be make so as to take at least one banana and one orange on selection = 31 × 15 = 465

Answer 2

Answer:

465

Step-by-step explanation:

Given: To make a selection so as to take ATLEAST 1 mango and 1 orange.

so

Minimum number of mangoes that can be selected=1

Maximum number of mangoes that can be selected=4

and

Minimum number of oranges that can be selected=1

Maximum number of oranges that can be selected=5

=(4C1+4C2+4C3+4C4)×(5C1+5C2+5C3+5C4+5C5)

=(4+6+4+1)×(5+10+10+5+1)

=15×31

=465.