A bag contains 4 red, 3 blue and 9 green balls. How many green balls should be removed such that the
difference between probability of drawing a green ball and probability of drawing a red ball is
1/2
Answers
Answered by
0
Answer:
Let x be the number of red balls to be subtracted.
According to the question,
35−x
20−x
=
5
2
5(20−x)=2(35−x)
100−5x=70−2x
x=10
Answered by
0
Answer:
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