A bag contains 4 red, 5 black and 6 white balls. A ball is drawn from the bag at random. Find the probability that the ball drawn is:
(i) white
(i) red
(iii) not black
(iv) red or white
Answers
Answered by
1
Answer:
i)P(E)=no.of white balls/no.of total balls=6/15
ii)P(E)=4/15
iii)P(E)=10/15=2/3
iv)P(E)=6+4/15=10/15=2/3
hope this helps!!
Answered by
0
Step-by-step explanation:
let event a be that ball is white
hence probability will be 6/15
let event b
total red balls 4
4 /15
3 ) 10 / 15
4) 10 / 15
Similar questions