A bag contains 4 red, 5 white and 2 blue balls. If 2 balls are randomly drawn, find the probability that both are of same color.
Answers
Answer:
17/55
Step-by-step explanation:
Find the total number of balls:
Total number of balls = 4 + 5 + 2 = 11
Find the probability that 2 balls drawn are the same color:
P(both balls are red) = (4/11)(3/10) = 6/55
P(both are white) = (5/11)(4/10) = 2/11
P(both are blue) = (2/11)(1/10) = 1/55
P(Both balls are the same color) = 6/55 + 2/11 + 1/55 = 17/55
Answer: 17/55
Answer:
The correct answer is 13/28
Step-by-step explanation:
We can solve this problem in two parts which is explained as under:-
Probability of Choosing 2-White:-
There is a 5/8 chance that a White marble will be chosen.
A white marble is chosen without replacement.
So, there are now 5–1=4 white marbles in a bag of 8–1=7 marbles.
So there is a 4/7chance that a white marble will be chosen the second time.
The total probability of choosing 2-White Marbles :
(5/8)∗(4/7)=20/56=5/14
Probability of Choosing 2-Black:
There is a 3/8 chance that a black marble will be chosen.
The marble is chosen and not replaced.
There are now 3–1=2 black marbles in a bag of 8–1=7 marbles.
So there is now a 2/7chance that a black marble will be chosen.
if we multiply the two fractions together we get,
(3/8)∗(2/7)=6/56=3/28
Finally
Probability of Choose 2 Marbles of Same Color = Probability of 2 White + Probability of 2 Black
=5/14+3/28
=13/28
Hence solved