Math, asked by spammer74, 6 months ago

A bag contains 4 red, 6 blue and 7 yellow balls. One ball is selected at random. What is the probability that it is (a) a red ball (b) blue or yellow ball ? (c) not blue ball ?​

Answers

Answered by Anonymous
4

Answer:

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a) Number of red balls = 4

Total number of balls = 4 + 6 + 7 = 17

Therefore probability of a red ball

= 4/17.

b) Number of the blue and yellow

= 6 + 7

= 13

Therefore probability of a blue or a yellow ball

= 13/17.

c) Total number of balls that are not blue

= Red balls + Yellow balls

= 4 + 7 = 11

Therefore probability of not a blue ball = 11/17.

Answered by Anonymous
1

Answer:

a) Number of 3’s on a dice = 1

Total number of possible outcomes = 6

(Since Sample space = {1, 2, 3, 4, 5, 6})

Therefore probability of getting 3 = 1/6.

b) Number of even numbers on a dice

= 3(2, 4, 6)

Total number of possible outcomes = 6

Therefore probability of getting an even number

= 3/6 = 1/2.

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