Question

A bag contains 4 red, 6 blue and 7 yellow balls. One ball is selected at random. What is the probability that it is (a) a red ball (b) blue or yellow ball ? (c) not blue ball ?​

Answer 1

Answer:

$\huge\underline\bold {Answer:}$

a) Number of red balls = 4

Total number of balls = 4 + 6 + 7 = 17

Therefore probability of a red ball

= 4/17.

b) Number of the blue and yellow

= 6 + 7

= 13

Therefore probability of a blue or a yellow ball

= 13/17.

c) Total number of balls that are not blue

= Red balls + Yellow balls

= 4 + 7 = 11

Therefore probability of not a blue ball = 11/17.

Answer 2

) Number of red balls = 4

Total number of balls = 4 + 6 + 7 = 17

Therefore probability of a red ball

= 4/17.

b) Number of the blue and yellow

= 6 + 7

= 13

Therefore probability of a blue or a yellow ball

= 13/17.

c) Total number of balls that are not blue

= Red balls + Yellow balls

= 4 + 7 = 11

Therefore probability of not a blue ball = 11/17.

mark me as brainliest answers