A bag contains 4 red 6 blue and a second bag contains 4 blue and 6 green balls. A ball is taken out from each bag. find the probablity that one ball is red and other ball is green the probability that an event A happens in one trail of an experiment is 0.4 three independent trails of the experiment are performed. find the probablity that the event A happens at least one
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Step-by-step explanation:
Number of green balls = 7
Number of red balls = 2
Number of blue balls = 5
Total number of balls = 14
P(E) = Number of Favorable Outcomes/Total Number of Possible Outcomes
Or number of event occurs/total number of events
So, probability of drawn balls that it is either a blue or a green
P(E) = (7+5)/14 = 12/14 = 6/7
hope it help
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