A bag contains 4 red and 4 black balls, another bag contains 2 red and 6 black balls. One of the two bags is selected at random and a ball is drawn from the bag which is found to be red. Find the probability that the ball is drawn from the first bag.
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the probability of first bag is 1 by 4
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Answer:
2/3
Step-by-step explanation:
Probability of selecting each bag is equal = 1/2
Let say Ball is drawn from Bag 1
Probability of selecting Bag 1 = 1/2
Probability of selecting red ball = 4/8 = 1/2
Let say Ball is drawn from Bag 2
Probability of selecting Bag 2= 1/2
Probability of selecting red ball = 2/8 = 1/4
probability that the ball is drawn from the first bag
= (1/2) (1/2) / ( (1/2)(1/2) + (1/2)(1/4))
= (1/2) /( 3/4)
= 4/6
= 2/3
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