Question

A bag contains 4 red balls, 3 yellow balls and 5 green balls. A ball is drawn from the bag
without looking into it. What is the probability of getting a green ball?

Answer 1

Answer:

5/12

the number of green balls dived by the total number of balls.

Answer 2

Answer:

Probability of getting a green ball is 5/12

Step-by-step explanation:

S={R1, R2, R3, R4, Y1, Y2, Y3, G1, G2, G3, G4, G5}

n(S)= 12

Let Event A = Getting a green ball

A={G1, G2, G3, G4, G5}

n(A)= 5

P(A)= n(A)/n(S)

     = 5/12