Question

a bag contains 4 red balls 5 black balls and 3 green balls a ball is drawn at random from bag find the probability that the ball drawn is not a green ball ​

Answer 1

Answer:

Total number of balls in the bag 5+4+3=12.

We denote the event of getting a red ball as R, that of getting a green ball G, that of getting a colored ball as C and that of getting a ball not green as

G

or not G.

There are 4+3=7 coloured balls, i.e. either red or green.

So, 7 outcomes favour the event C.

P(C)=

12

Number of outcomes which favour C

∴P(C)=

12

7

Step-by-step explanation:

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