Question

A bag contains 4 red balls ,7 white balls ,3 green and 6 black balls .if one balls is drawn at random ,find the probability that it is (I) black (II) red (III) not white​

Answer 1

Answer:

(1)p(of getting black ball)=6/20

(2)p(of getting red ball)=4/20

(3)p(of getting not white)=13/20

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Answer 2

Answer:

White balls = 7

Red balls = 4

Green balls = 3

Black balls = 6

Total = 20

Probability that ball will be black:-

Black balls = 6

Total balls = 20

$Probability = \frac{6}{20}$

$= \frac{3}{10}$

Probability that ball will be red:-

Red balls = 4

Total balls = 20

$Probability = \frac{4}{20}$

$= \frac{1}{5}$

Probability that ball will not be white:-

Number of white balls = 7

Non white balls = 13

Total balls = 20

$Probability = \frac{13}{20}$

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