Question

A bag contains 4 red balls, 7 white balls, 3green and 6 black balls. If one ball is draw at random, find the probability that it is

(1) black
(ii) red
(iii) not white.​

Answer 1

$\huge\mathfrak\red{Here's\:your\:answer}$

So total number of balls = 4+7+3+6= 20

so 1) 6/20 = 3/10

2) 4/20 = 1/5

3) 13 /20