Question

A bag contains 4 tickets numbered 1,2,3,4 and another bag contais 6 tickets numbered2,4,6,7,8,9 one bag is chosen and a tickt is drawn the probability that the ticket bears the number 4

Answer 1

probability of bag choose = 1/2

probability of number 4 choose to first bag
= 1/4
probability of number 4 choose to second bag
= 1/6

then

individual choose the number 4 = (1/4+1/6)*1/2

= (3+2)/(12*2) = 5/24

I hope it will help you..

Answer 2

Answer:

P(chossing bag) = 1/2

P(no. 4 chosen from 1st bag) = 1/4

P(no. 4 chosen from 2nd bag) = 1/6

P(ticket bears the no. 4) = 1/4+1/6 * 1/2

= 5/12 * 1/2

= 5/24