Question

A bag contains 4 white, 5 red and 6 blue balls. Three balls are drawn at random from the bag. The probability that all of them are red, is:
A.43122
B.43181
C.2/91
D.2/77

Answer 1

I think this would help you!

Answer 2

Answer:

2/91

Step-by-step explanation:

Let S be the sample space.

Then, n(S) = number of ways of drawing 3 balls out of 15 = 15C3 =15*14*133*2*1= 455.

Let E = event of getting all the 3 red balls.

n(E) = 5C3 = 5*42*1 = 10.

=> P(E) = n(E)/n(S) = 10/455 = 2/91.