A bag contains 4 white, 5 red and 6 green balls. Three balls are picked up randomly without replacement. What is the probability that a white, a red and a green ball is drawn?
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Given:
A bag contains 4 white, 5 red and 6 green balls.
The total Number of balls = 15
Three balls are picked up randomly without replacement
To Find:
The probability that a white, a red and a green ball is drawn.
Solution:
Here the order doesn't matter.
- There are 3 x 2 x 1 = 6 possible ways of choosing the balls.
- eg : white first , red second and green third.
- or red first, green second and white third.
Now lets consider the probability.
- P(choosing white ball) = 4/15
- P(choosing red if white already taken) = 5/14
- P( choosing green if read and white taken) = 6/13
probability that a white, a red and a green ball is drawn,
- P = 6 x (4 x 5 x 6 / 15 x 14 x 13)
- P = 6 x 120/2730
- P = 0.2637
The probability that a white, a red and a green ball is drawn is 0.2637
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