Question

A bag contains 4 white, 5 red and 6 green balls. Three balls are picked up randomly without replacement. What is the probability that a white, a red and a green ball is drawn?

Answer 1

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Answer 2

Given:

A bag contains 4 white, 5 red and 6 green balls.

The total Number of balls = 15

Three balls are picked up randomly without replacement

To Find:

The probability that a white, a red and a green ball is drawn.

Solution:

Here the order doesn't matter.

• There are 3 x 2 x 1  = 6 possible ways of choosing the balls.

• eg : white first , red second and green third.

• or red first, green second and white third.

Now lets consider the probability.

• P(choosing white ball) = 4/15
• P(choosing red if white already taken) = 5/14
• P( choosing green if read and white taken) = 6/13

probability that a white, a red and a green ball is drawn,

• P = 6 x  (4 x 5 x 6 / 15 x 14 x 13)
• P  = 6 x 120/2730
• P = 0.2637

The probability that a white, a red and a green ball is drawn is 0.2637