Question

A bag contains 4 white and 5 blue balls. They are mixed thoroughly and one ball is drawn at random. What is the probability of getting (i) a white ball? (ii) a blue ball?

Answer 1

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Answer 2

$Number \: of \: balls \: in \:a \:bag \\= 4(white) + 5(blue) \\= 9$

$\blue{ Number \:of \: total \: possible }\\\blue{outcomes = 9 \: ---(1)}$

$a ) Number \:of \: favourable \: outcomes \\= Number \:of \: white \:balls \\= 4 \: --(2)$

$Probability ( Getting\:a \:white \:ball) = \frac{(2)}{(1)} \\= \frac{4}{9}$

$b) Number \:of \: favourable \: outcomes \\= Number \:of \: blue \:balls \\= 5 \: --(3)$

$Probability ( Getting \:a\:blue \:ball) = \frac{(3)}{(1)} \\= \frac{5}{9}$

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