A bag contains 4 white and 6 black balls. one ball is drawn and laid aside without noticing its colour. Another ball is then drawn. what is the probability that the 2nd ball is black?
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Total number of balls in bag = 10 (4 white and 6 black)
Here we have 2 cases:
First Case: The first ball drawn was black:
Then number of black balls remaining = 6-1 = 5
Probability of second ball being black = 5/9
Second Case: The first ball drawn was not black:
Then number if black balls remaining = 6
Probability of second ball being black = 6/9
Please let me know if there are any queries.
FYI... The equation for Probability is given by:
Probability = Number of favourable outcomes / Total number of outcomes
Here we have 2 cases:
First Case: The first ball drawn was black:
Then number of black balls remaining = 6-1 = 5
Probability of second ball being black = 5/9
Second Case: The first ball drawn was not black:
Then number if black balls remaining = 6
Probability of second ball being black = 6/9
Please let me know if there are any queries.
FYI... The equation for Probability is given by:
Probability = Number of favourable outcomes / Total number of outcomes
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