a bag contains 4 white and 6black balls one ball is drawn and laid aside without noticing iys colour. another ball is then drawn what is the probability that the second ball is black
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total ball left = 9
total no. of outcomes = 6
p(E) = 6/9
= 2/3
total ball left = 9
total no. of outcomes = 6
p(E) = 6/9
= 2/3
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Total no : of balls = 10
As first ball is drawn , the total no : of balls remaining = 10 - 1 = 9.
No:of black balls = 6
probability of black ball = 6 / 9 = 2/3
As first ball is drawn , the total no : of balls remaining = 10 - 1 = 9.
No:of black balls = 6
probability of black ball = 6 / 9 = 2/3
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