Question

A bag contains 4 white balls, 5 red balls, 2 black balls and 4 green balls.A ball is drawn at random from the bag. Find the probability that it is
(i) black, (ii) not green, (iii) red or white, (iv) neither red nor green.
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Answer 1

Answer:

Probability = (number of favorable outcomes)/(Total number of outcomes) A bag contains 4 white balls, 5 red balls, 2 black balls and 4 green balls. Total numbers of balls = 4 + 5 + 2 + 4 = 15 (i) Total numbers of black balls = Numbers of favorable outcomes= 2 P(getting a black ball) = 2/15 (ii) Total numbers of green balls = 4 Numbers of non-green balls = 15 – 4 = 11 P(not green ball) = 11/15 (iii) Total numbers of red and white balls = 5 + 4 = 9 P(red ball or white ball) = 9/15 = 3/5 (iv) Total numbers of red and green balls = 5 + 4 = 9 Number of balls which are neither red nor green = 15 – 9 = 6 P (getting neither red nor green ball) = 6/15 = 2/5