A bag contains 4 white balls and 5 black balls. Another bag contains 3 white and 4 blak balls. A ball is taken out from the first bag and without seeing its colour is put in the second bag. A ball is taken out from the latter. Find the probability that the ball drawn is white.
Answers
Answer:
Probability: 31/72
Step-by-step explanation:
Bag1: 4 white 5 black
Bag2: 3 white 4 black
1. If Ball taken out from bag1 is white , then:
Its probability: 4/(4+5) = 4/9
Bag1: 3 W and 5 B Bag2: 4 W and 4 B
Probability that the ball drawn from bag2 is white: 4/(4+4) = 1/2
2. If the ball taken out from bag1 is black, then:
its probability = 5/(4+5) = 5/9
Bag1: 4 W & 4 B Bag2: 3 W & 5 B
Probability that the ball drawn from bag2 is white: 3/(3+5) = 3/8
Overall probability: 4/9 * 1/2 + 5/9 * 3/8 = 31/72
Answer:
Step-by-step explanation:
1. If Ball taken out from bag1 is white , then:
Its probability: 4/(4+5) = 4/9
Bag1: 3 W and 5 B Bag2: 4 W and 4 B
Probability that the ball drawn from bag2 is white: 4/(4+4) = 1/2
2. If the ball taken out from bag1 is black, then:
its probability = 5/(4+5) = 5/9
Bag1: 4 W & 4 B Bag2: 3 W & 5 B
Probability that the ball drawn from bag2 is white: 3/(3+5) = 3/8
Overall probability: 4/9 * 1/2 + 5/9 * 3/8 = 31/72