A bag contains 4 yellow balls, 3 green balls and 5 red balls. A ball is drawn at random. Find the probability of getting a ball which is not yellow.
Answers
Step-by-step explanation:
Random Experiment: A ball is drawn at random
Let 'S' be the sample space
S = { Y1, Y2, Y3, Y4, G1, G2, G3, R1, R2, R3, R4, R5 }
n(S) = 12
'A' is the event to draw a ball which is not yellow
A = { G1, G2, G3, R1, R2, R3, R4, R5 }
n(A) = 8
P(A) = n(A)/n(S)
= 8/12
= 2/3
Hence, the probability of getting a ball which is not yellow is 2/3
Answer:
2/3
Explanation:
We know that the ball which is not yellow = P
total no. of balls in the bag = 4+3+5 = 12
We denote the event of getting a red ball R, that of getting a yellow ball G, that of getting a coloured ball as C and that of getting a ball not yellow
There are 5+3 = 8 ball which are not yellow i.e. white or red, so there are 8 outcomes that favour the event not Y
Therefore, P (notY) = 8/12 = 2/3
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