A bag contains 42 coins including denominations of 50 pass, 25 paisa, and 10 paisa. If the number of 25 paisa coins is three times that of 50 paisa coins and the total number is Rs 9.30, find the number of 10 paisa coins.
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Step-by-step explanation:
- let the number of 50p coins be x.
- then no. of 25p coins is 3x [according to question]
- total coins = 42
- no. of 10p coins = 42- (x+3x)
- now , 50p = 1/2 Rs
- 25p = 1/4 Rs and 10p = 1/10 Rs
so, total amount = Rs 9.3
x*1/2 + 3x*1/4 + (42-4x)*1/10 = 9.3
on solving it you will get x = 6
hence, no. of 10p coins = 42-4*6 = 18
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