Question

A bag contains 459 coins of three different types, 1 rupee, 50 paisa, and 25 paisa, in the ratio of 13: x: (x+10), respectively. Find the value of x, if bag contains coins worth Rs. 234.

Answer 1

number of coins = total value of those coins/ value of one coin

total value of 1 rs , 0.5 rs and 0.25 rs coins are 5x , 3x and x respectively

number of 1 rupee coin = a = 5x/1 = 5x

number of 0.5 rupee coin = b = 3x/0.5 = 6x

number of 0.25 rupee coin = c = x/0.25 = 4x

N = total number of coins = 465

N = a + b + c

465 = 5x + 6x + 4x

x (15) = 465

x = 465/15

x = 31

number of 1 rupee coin = a = 5x = 5x 31 = 155

number of 0.5 rupee coin = b = 6x = 6 x 31 = 186

number of 0.25 rupee coin = c  = 4x = 4 (31) = 124

Answer 2

Answer:

Step-by-step explanation: