Question

A bag contains 5 black, 7red and 3 white balls. A ball is drawn from the bag at random. Find the probability that the ball drawn is :
(i)red
(ii)black or white
(iii)not black

Answer 1

SOLUTION :  

GIVEN : Number of red balls = 7

Number of white balls = 3

Number of black balls = 5

Total number of balls in a bag = 7 + 3 + 5 = 15

Total number of outcomes = 15

(i) Let E1 = Event  of selecting that a  ball drawn is red

Number of red balls = 7

Number of outcome favourable to E = 7

Probability (E1) = Number of favourable outcomes / Total number of outcomes

P(E1) = 7/15

Hence, the required probability of getting a red ball , P(E1) = 7/15 .

(ii) Let E2 = Event  of selecting that a ball drawn is black or white

Number of outcome favourable to E = 5 + 3 = 8

Probability (E2) = Number of favourable outcomes / Total number of outcomes

P(E2) = 8/15

Hence, the required probability of getting a red ball , P(E2) = 8/15 .

(iii) Let E3 = Event  of selecting that a  ball drawn is not black

Number of balls that are not black = (7+3) = 10

Number of outcome favourable to E3 = 10

Probability (E3) = Number of favourable outcomes / Total number of outcomes

P(E3) = 10/15 = 2/3

Hence, the required probability of getting a a  ball drawn is not black, P(E3) = 2/3 .

HOPE THIS ANSWER WILL HELP  YOU….

Answer 2

(I) red = 7/15
(2) black or white = 8/15
(3) not black = 10/15= 2/3
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