Question

A bag contains 5 blue balls 4 green balls . a ball is drawn at random from the bag . find the probability that the ball drawn is i)blue ii)not blue​

Answer 1

Step-by-step explanation:

Answer:Total balls = 9Blue balls = 5Green balls = 4Probability that the ball drawn is blue = 5/9Probability that the ball drawn is green = 4/9Pls mark my answer…

Answer 2

Answer:

Since, total no. of balls = 5+7+4+2 = 18

(i) No. of balls that are white or blue = 5+2 = 7

∴ Required probability =

18

7

(ii) No. of balls that are red or black = 7+4 = 11

∴ Required probability =

18

11

(iii) No. of balls that are not white = 7+4+2 = 13

∴ Required probability =

18

13

(iv) No. of balls that are neither white nor black = 7+2 = 9

∴ Required probability =

18

9

=

2

1