Question

A bag contains 5 blue marbles, 2 black marbles, and 3 red marbles. A marble is randomly drawn from the bag. The probability of not drawing a black marble is . The probability of drawing a red marble is

Answer 1

Given conditions ⇒
No. of the blue marbles in the bag = 5
No. of the black marbles in the bag = 2
No. of the red marbles in the bag = 3
∴ Total number of the Marbles in the bag = 5 + 2 + 3
    = 10 marbles.

In First Case,
To find ⇒ Probability of not drawing the black marble.
Number of red and blue marbles in the bag = 5 + 3
 = 8 marbles.

∵ P[of not taking out th black Marbles] = No. of Red and Blue Marbles/Total number of Marbles.
∴ P[E] = 8/10
 = 4/5

Hence, the probability of not taking out the black marbles is 4/5.


In Second Case,
To Find ⇒ Probability of drawing the red marble.

∵ P[of drawing the rec Marble] = No. of Red Marbles/Total number of Marbles.
∴ P[R]= 3/10

Hence, the probability of taking out the red marbles is 3/10.


Hope it helps.

Answer 2

Answer:

he is right

Step-by-step explanation: