Question

A bag contains 5 green, 7 red and 3 blue
balls. A ball is drawn at random. Find the
probability of drawing a red ball. If we
draw a blue ball and then a red ball, find
the sample space and the probability of
drawing a green ball.​

Answer 1

probability of red ball is

total number of ball=5+7+3=15

red ball =7/15

green ball =5/15=1/3

Answer 2

Answer:

Total no. of balls=4+6+3=13

Total no. of ways one ball out of 7,n(S)=13C 1

No.of ways of drawing 1 ball,none of then is blue,n(E)=13−6=7C 1

∴probability=n(E)/n(S)=7/13