Question

.A bag contains 5 green marbles, 3 blue marbles, 2 red marbles and

2 yellow marbles. One marble is drawn out randomly. Find the

probability of p(green) , p(blue), p(red) and p(yellow)​

Answer 1

Answer:

Total no. of possible outcomes = 5+3+2+2 = 12.

P (green) = 5/12.

P (blue) = 3/12 = 1/4.

P (red) = 2/12 = 1/6.

P (yellow) = 2/12 = 1)6.

Hope this helps!!!!