Question

.A bag contains 5 green marbles, 3 blue marbles, 2 red marbles and

2 yellow marbles. One marble is drawn out randomly. Find the

probability of p(green) , p(blue), p(red) and p(yellow)​

Answer 1

Answer:

total marbles=12

probability of green = 5/12

probability of blue=3/12=1/4

probability of red=2/12=1/6

probability of yellow=2/12=1/6

Answer 2

Answer:

(i) 1 / 2

(ii) 3 / 10

(iii) 1 / 5

(iv) 0

Step-by-step explanation:

Total no. of marbles = 10

(i)

No. of possibilities of getting green = 5

P(green) = No. of possibilities of getting green / Total no. of marbles

              = 5 / 10

              = 1 / 2

(ii)

No. of possibilities of getting blue = 3

P(blue) = No. of possibilities of getting blue / Total no. of marbles

            = 3 / 10

(iii)

No. of possibilities of getting red = 2

P(red) = No. of possibilities of getting red / Total no. of marbles

          = 2 / 10

          = 1 / 5

(iv)

No. of possibilities of getting yellow = 0

P(yellow) = No. of possibilities of getting yellow / Total no. of marbles  

               = 0 / 10

               = 0

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