Question

A bag contains 5 mangos, 4 oranges, 6 guavas. Find the probability of the
following events, if one of the fruits is picked from the bag at random
(i) It is the a mango (ii) It is a orange or a guava (iii) It is not an orange.​

Answer 1

Answer:

P(A) = 1/3

P(B) = 2/3

P(C) = 11/15

Step-by-step explanation:

n(S) = 5+4+6=15

n(M) = 5

n(O) = 4

n(G) = 6

Event A : It is the a mango

P(A) = n(M)/n(S)

= 5/15

P(A) = 1/3

Event B : It is a orange or a guava

P(B) = n(O+G)/n(S)

= 10/15

P(B) = 2/3

Event C : It is not an orange

P(C) = n(M+G)/n(S)

P(C) = 11/15

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Answer 2

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