Question

A bag contains 5 oranges, 4 bananas and 3 apples. rohit wants to eat a banana or an apple.he draws a fruit from the bag randomly. what is the probability that he will get a fruit of this choice? 3.5/12 12-jul 12-may none of the above

Answer 1

total outcomes = 12
he wants to apple or banana, thus no. of apple and banana together = 4+3=7
probability= favourable outcomes/total outcomes
= 7/12

Answer 2

Answer:

$\frac{7}{12}$

Step-by-step explanation:

Number of oranges = 5

Number of apples = 3

Number of bananas = 4

Total number of fruits = $5+3+4=12$

So, probability of getting an apple :

Total events = 12

favorable events = Number of apples = 3

So,  probability of getting an apple =$\frac{3}{12}$

So, probability of getting a banana :

Total events = 12

favorable events = Number of bananas = 4

So,  probability of getting a banana  =$\frac{4}{12}$

Now, probability of getting an apple or banana=$\frac{4}{12}+\frac{3}{12}$

                                                                             = $\frac{7}{12}$

Hence the probability that he will get a fruit of this choice is $\frac{7}{12}$