Question

A bag contains 5 red, 6 black and 4 blue balls. A ball is drawn at random from the bag, find
the probability that the ball drawn is
a) blue
b) neither red nor blue
​

Answer 1

Answer:

a)4/15

b)6/15

Step-by-step explanation:

red balls n(r)=5

black balls n(b)=6

blue balls n(B)=4

total balls n(s)=15

probability of blue ball=n(B)/n(s)

=4/15

probability of neither red nor blue means only black balls=n(b)/n(s)

=6/15

Answer 2

Answer:

bule= 4/15

black=6/15

Step-by-step explanation:

add total balls= 15(5+6+4)

then how many bule balls are there 4 and total numbers of ball 15 (4/15) so the answer for for bule ball is 4/15

next neither red nor blue

then black ball 6/ 15.