Question

A bag contains 5 red, 6 black and 4 white balls. A ball is drawn at random from
the bag. Find the probability that the ball drawn is
i) white ii) not black iii) red or black​

Answer 1

Given

5 Red balls ,6 black balls and 4 white balls

To Find

Probability when the ball drawn is i) white ii) not black iii) red or black

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

$\sf \bold{ \red{ \: probability}} = \dfrac{no.of \: favourable \: outcomes}{total \: no \: of \: outcomes}$

(I) Probability that the ball drawn is white

From above all 3 coloured balls white is 4 and total number of balls is 5+6+4=15 balls

P(white ball)=Number of favourable outcomes/total number of outcomes

P(white ball)=4/15

ii) Probability of not black balls means the remaining balls will come except black

remaining balls =5+4=9

total outcomes =15

P(not black balls)=9/15=3/5

(iii) Probability of red or black

Either red comes or black so we take both possibilities.

Favorable outcomes =6+5=11

total number of outcomes =15

P(red or black)=11/15

Answer 2

Answer:

❀ǫᴜᴇsᴛɪᴏɴ ɢɪᴠᴇɴ

A bag contains 5 red, 6 black and 4 white balls. A ball is drawn at random from

the bag. Find the probability that the ball drawn is

i) white ii) not black iii) red or black

❀ʀᴇǫᴜɪʀᴇᴅ ᴀɴsᴡᴇʀ:

$probability= \frac{total \: no \: of \: outcomes}{no.of \: favourable \: outcomes}$

(I) Probability that the ball drawn is white

From above all 3 coloured balls white is 4 and total number of balls is 5+6+4=15 balls

P(white ball)=Number of favourable outcomes/total number of outcomes

P(white ball)=4/15

ii) Probability of not black balls means the remaining balls will come except black

remaining balls =5+4=9

total outcomes =15

P(not black balls)=9/15=3/5

(iii) Probability of red or black

Either red comes or black so we take both possibilities.

Favorable outcomes =6+5=11

total number of outcomes =15

P(red or black)=11/15