A bag contains 5 red, 8 green and 7 white balls. One ball is drawn at random from the bag. What is the probability of getting a white ball or a green ball?
Answers
Given : A bag contains 5 red, 8 green and 7 white balls. One ball is drawn at random from the bag.
Solution :
We have , Number of red balls = 5
Number of green balls = 8
Number of white balls = 7
Total number of balls in a bag = 5 + 8 + 7 = 20
Total number of outcomes = 20
Let E = Event of getting a white or a green ball
Number of white or a green ball = 8 + 7 = 15
Number of outcome favourable to E = 15
Probability (E) = Number of favourable outcomes / Total number of outcomes
P(E) = 15/20 = 3/4
Hence, the required probability of getting a white or a green ball , P(E) = 3/4
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Step-by-step explanation:
Answer:
Number of red balls = 5
Number of green balls = 8
Number of white balls = 7
Total number of balls = 5 + 8 + 7
= 20
i). P(a white or green ball) = P(a white ball) + P(a green ball)
= 7/20 + 8/20
= 15/20
= 3/4
ii). P(neither a green ball not a red ball) = P(a white ball)
= 7/20
Number of cards in the deck = 52
Number of non-face cards = 40
Number of black kings = 2
Number of red queen = 2
i). P(a non-face card) = 40/52
= 10/13
ii). P(a black king or a red queen) = P(a black king) + P(a red queen)
= 2/52 + 2/52
= 4/52
= 1/13