a bag contains 5 red 8 green and 7 white balls one ball is drawn at random from the bag. what is the probability of getting I) a white ball or a green ball? II) neither red nor white? III) not a green BALL?
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Answer:
- white balls 7/20 green balls 8/20
- 8/20
- 12/20
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Total balls in bag= 20
No of red ball= 5
No of green ball= 8
No of white ball = 7
i) no of white ball + no of green ball/ total no of ball
15/20= 3/4
ii) no of green ball / total no of ball = 8/20= 2/5
iii) no of white ball+ no of red ball/ total no of ball=12/20= 6/10=3/5
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