A bag contains 5 red, 8 green and 7 white balls. One ball is drawn at random from the bag, find the probability of getting (i) a white ball or a green ball. (ii) neither a green ball not a red ball. OR One card is drawn from a well shuffled deck of 52 playing cards. Find the probability of getting (i) a non-face card (ii) a black king or a red queen.
Answers
total balls :20
1)prob. of getting a while ball or a green ball.
15/20=3/4
2)7/20
OR
total cards =52
total card left=40
1)40/52
2)4/52
Answer:
Number of red balls = 5
Number of green balls = 8
Number of white balls = 7
Total number of balls = 5 + 8 + 7
= 20
i). P(a white or green ball) = P(a white ball) + P(a green ball)
= 7/20 + 8/20
= 15/20
= 3/4
ii). P(neither a green ball not a red ball) = P(a white ball)
= 7/20
Number of cards in the deck = 52
Number of non-face cards = 40
Number of black kings = 2
Number of red queen = 2
i). P(a non-face card) = 40/52
= 10/13
ii). P(a black king or a red queen) = P(a black king) + P(a red queen)
= 2/52 + 2/52
= 4/52
= 1/13