A bag contains 5 red, 8 green and 7 white balls, One ball is drawn at random from the bag. What is the probability of getting a white ball or a green ball?
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SOLUTION :
GIVEN : Number of red balls = 5
Number of green balls = 8
Number of white balls = 7
Total number of balls in a bag = 5 + 8 + 7 = 20
Total number of outcomes = 20
Let E = Event of getting a white or a green ball
Number of white or a green ball = 8 + 7 = 15
Number of outcome favourable to E = 15
Probability (E) = Number of favourable outcomes / Total number of outcomes
P(E) = 15/20 = 3/4
Hence, the required probability of getting a white or a green ball , P(E) = 3/4
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total number of ball = 5 + 8 + 7 = 20
probability of getting green ball is = total number of green ball / total number of ball = 8 / 20 = 2/ 5
probability of getting white ball is = total number of white ball/ total number of balls = 7/20
probability of getting green ball is = total number of green ball / total number of ball = 8 / 20 = 2/ 5
probability of getting white ball is = total number of white ball/ total number of balls = 7/20
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