A bag contains 5 red, 8 white and 7 black balls. A ball is drawn at random from the bag. Find the probability that the drawn ball is
i) red or white
ii) not a white ball
Answers
Answer:
Total no. of balls in the bag is 20 (5 red, 7 black and 8 white)
Solution(i):
No. of red or white balls in bag is 13 (5 red and 8 white)
Therefore,
13
C
1
( Selecting 1 out of 13 items) times out of
20
C
1
( Selecting 1 out of 20 items) a red or white ball is picked.
Let E be the event of drawing a red or white ball from bag
We know that, Probability P(E) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
20
C
1
13
C
1
=
20
13
Solution(ii):
No. of non-black balls in bag is 13 (5 red and 8 white)
Therefore,
13
C
1
( Selecting 1 out of 13 items) times out of
20
C
1
( Selecting 1 out of 20 items) a non-black ball is picked.
Let E be the event of drawing a non-black ball from bag
We know that, Probability P(E) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
20
C
1
13
C
1
=
20
13
Solution(iii):
No. of neither black nor white balls in bag is 5 (5 red balls)
Therefore,
5
C
1
( Selecting 1 out of 5 items) times out of
20
C
1
( Selecting 1 out of 20 items) a neither white nor black ball is picked.
Let E be the event of drawing neither white nor black ball from bag
We know that, Probability P(E) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
20
C
1
5
C
1
= 20/4
= 4/1