Math, asked by roly7549, 1 year ago

A bag contains 5 red and 3 blue balls. If 3 balls are drawn at random without replacement then find the probability of getting exactly one red ball.

Answers

Answered by rathibhagwati3
4

Answer:

Step-by-step explanation:

Attachments:
Answered by sharonr
1

The probability of getting exactly one red ball is 15/56

Solution:

The probability of an event is given as:

Probability = \frac{ \text{ number of favorable outcomes }}{ \text{ total number of possible outcomes }}

From given,

A bag contains 5 red and 3 blue balls

Total number of possible outcomes = 5 + 3 = 8

3 balls are drawn at random without replacement

Then find the probability of getting exactly one red ball

Therefore,

P(exactly\ one\ ball) = P(R) \times P(B) \times P(B) + P(B) \times P(R) \times P(B) +P(B) \times P(B) \times P(R)

P= \frac{5}{8} \times \frac{3}{7} \times \frac{2}{6} + \frac{3}{8} \times \frac{5}{7} \times \frac{2}{6} + \frac{3}{8} \times \frac{2}{7} \times \frac{5}{6}

P = \frac{15}{56}

Thus the probability of getting exactly one red ball is 15/56

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