Question

A bag contains 5 red and 4 green ball two drawing of 3 balls each are made with replacement what is the probability that the first is red and second is green

Answer 1

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Here is the solution:

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Total number of balls = 5 + 4 + 3 = 12

Number of red balls = 5

Number of green balls = 4

P(red ball) = 5/12

P(green ball) = 4/12 = 1/3

P(red and then green) = (5/12) ( 1/3) = 5/36

Answer: The probability of a red and the a green is 5/36