A bag contains 5 red and 4 pink marbles.Two are drawn without replacement. what is the probability that both are red .
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Let A be the event that first marble is white.
let B be the event that second marble is white.
Let C be the event that first marble is not white.
Applying Bayes theorem
P(A/B)=(P(B/A)P(A))/(P(B/A)P(A)+P(B/C)P(C))
therefore,
P(A/B)= (4/9 xx 3/8)/((4/9 xx 3/8)+(5/9 xx 4/8))=12/32
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