Question

A bag contains 5 red and 9 white balls,one ball is drawn at random from the bag ,find the probability of getting a) a white ball b)a red ball

Answer 1

Total number of balls= 5red+9 white

=14

Number of white balls=9

Therefore,

$P(a \: white \: ball) = \frac{total \: no \: of \: balls \: }{white \: ball}$

$= \frac{14}{9}$

$P(a \: red \: ball) = \frac{total \: no \: of \: balls \: }{red \: ball}$

$= \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \frac{14}{5}$