Question

. A bag contains 5 red and some blue balls,

(i) if probability of drawing a blue ball from the bag is twice that of a red ball, find the

number of blue balls in the bag.

(ii) if probability of drawing a blue ball from the bag is four times that of a red ball, find the

number of blue balls in the bag.

Answer 1

Answer:

(i) Let b be the number of blue balls, b+5 is the sample space

Pr(b)=Pr(Red)

b/b+5=2(5/b+5)

b=10

(ii) Same concept applies

b/b+5=4(5/b+5)

b=20

Hope this helps :)

Step-by-step explanation:

Answer 2

Answer:

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Step-by-step explanation:

no. of red balls = 5

no. of blue balls = a

total no. of balls = [a + 5]

(i)  P (B) = 2 P (R)

   ⇒   a/[a + 5]  =  2 × 5/[a + 5]

   ⇒  a = 10

   ∵ no . of blue balls = 10

(ii)   P (B) = 4 P (R)

  ⇒   a/[a + 5]  =  4 × 5/[a + 5]

  ⇒  a = 20

   ∵ no . of blue balls = 20