Math, asked by sruthyrajesh1982, 10 months ago

A bag contains 5 red ball ,8 white balls ,4 green balls and 7 black balls. if one ball is drawn at random, find the probability that it is:
1. Red or white
2.not a white ball

Answers

Answered by Anonymous

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$\huge \tt {ANSWER:}$

$\small \tt {Total \: number \: of \: Balls \: in \: the \: bag} \\ \small \tt { = 5 + 8+4+7 = 24}$

$\small \tt {1. \: Total \: number \: of \: Red \: and \: white \: balls} \\ \small \tt {= 5+8 = 13}$

$\small \tt {Probability \: of \: getting \: a \: Red/White \: Ball} \\ \small \tt { = \frac {13}{24} = 0.54166..... or \: 0.542 ( approx. )}$

$\small \tt {2. \: Total \: number \: of \: Red \: and \: Green \: and \: Black} \\ \small \tt { =5+4+7 = 16}$

$\small \tt {Probability \: of \: getting \: a \: Non \: white \: Ball} \\ \small \tt { = \frac {16}{24} = 0.66.... or \: 0.67 ( approx. )}$

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