Question

a bag contains 5 red ball ,8 white balls ,4 green balls and 7 black balls. if one ball is drawn at random, find the probability that it is:
i) white ball
ii) green ball
iii) not a red ball

Answer 1

this is the answer to your question

Answer 2

Given:

Number of red balls=5

Number of white balls=8

Number of green balls=4

Number of black balls=7

To find:

Probability of picking a white ball, green ball, not a red ball

Solution:

We can find the solution by following the given steps -

The probability of an event can be determined by dividing the number of favorable events and total events.

Total number of balls= green balls+ red balls+ black balls+white balls

=4+5+7+8

=24 balls

So, the probability of picking a white ball= Number of white balls/ Total number of balls

=8/24

=1/3

The probability of picking a green ball= Number of green balls/ Total number of balls

=4/24

=1/6

The probability of not picking a red ball= Total number of balls- number of red balls/ Total number of balls

=19/24

Therefore, the probability of picking a white, green, and not a red ball is 1/3, 1/6, 19/24, respectively.