A bag contains 5 red balls 6 green balls and 2 black balls balls.One of the balls is removed from the bag. What is the probability of selecting a black ball
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Answered by
3
Given that in a bag 3 types of balls are present
Red balls = 5
Green balls = 6
Black balls =2
One ball is removed from the bag = only 12 balls will be left
Total no. of balls in a bag =5 + 6 + 2= 13
No. of favourable outcomes = 1
No. of total outcomes = 13
Probability to get black ball = 1/13
Red balls = 5
Green balls = 6
Black balls =2
One ball is removed from the bag = only 12 balls will be left
Total no. of balls in a bag =5 + 6 + 2= 13
No. of favourable outcomes = 1
No. of total outcomes = 13
Probability to get black ball = 1/13
Answered by
4
Total=5+6+2=13
P(red) 5/13
P(green) 6/13
P(black) 2/13
When one ball is removed it will be 13-1 ball been removed is 12
Probability of selecting a black ball is 2/13.if wrong pls correct me ,thanks
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