a bag contains 5 red balls, 8 white balls, 4 green balls, 7 black balls. if one ball is drawn at random, find the probability that isn't green.
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Answer:
no. of red balls- 5
no.of white balls- 8
no. of green balls-4
no. of black balls-7
probability(green balls) = no. of green balls / total balls
probability(green balls) = 4/24 = 1/6
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3
Red ball = 5
white ball = 8
green ball =4
black ball = 7
total ball =24
probability = 20/24
white ball = 8
green ball =4
black ball = 7
total ball =24
probability = 20/24
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