Question

a bag contains 5 red balls 8 white balls 4 green balls and 7 black balls one ball is drawn at random find the probability that is not green​

Answer 1

probability = number of favourable outcomes / no. of possible outcomes

probability that the ball drawn out is not green = probability that the ball is of other colour (red, white, and black)

hence the probabilty that the ball is not green

= 5+8+7 / 24

= 5/6

and, its a good chance.

Answer 2

AnswEr :

In the bag,

• No. of red balls = 5

• No. of white balls = 8

• No. of green balls = 4

• No. of black balls = 7

Now, let's calculate the total number of balls present in the bag !

Total no. of balls in the bag :

$\longrightarrow$ No. of red balls + No. of white balls + No. of green balls + No. of black balls

$\longrightarrow$ 5 + 8 + 4 + 7

$\longrightarrow$ 24

Now,

• No. of balls that aren't green = 5 + 8 +7 = 20

Let's calculate the Probability,

$\longrightarrow\sf \: Probability = \dfrac{No. \: of \: favorable \: outcomes}{Total \: no. \: of \: outcomes}$

$\longrightarrow \sf \: Probability = \dfrac{20}{24 }$

$\longrightarrow \sf \: { \underline{ \boxed{ \frak{ \purple{Probability = \dfrac{5}{6}}}}}} \: \: \bigstar$

Therefore, the Probability that the ball drawn is not green is 5/6.