Question

A bag contains 5 red balls, 8 white balls , 4 green balls and 7 black balls.

One ball is drawn at random, find the probability that it is (i) black

(ii) not white
solutions​

Answer 1

Answer:

Since, total no. of balls = 5+7+4+2 = 18

(i) No. of balls that are white or blue = 5+2 = 7

∴ Required probability =

18

7

(ii) No. of balls that are red or black = 7+4 = 11

∴ Required probability =

18

11

(iii) No. of balls that are not white = 7+4+2 = 13

∴ Required probability =

18

13

(iv) No. of balls that are neither white nor black = 7+2 = 9

∴ Required probability =

18

9

=

2

1

Answer 2

answer-

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